Saulty
EV ZEIN
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- Jan 27, 2010
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OK here is the puzzle for you. In a room with 365 people (no twins are present in the room) what are the odds of 3 people having the same birthday?
OK here is the puzzle for you. In a room with 365 people (no twins are present in the room) what are the odds of 3 people having the same birthday?
OK here is the puzzle for you. In a room with 365 people (no twins are present in the room) what are the odds of 3 people having the same birthday?
are we ignoring the possibility of TWINS? http://video.adultswim.com/tim-and-eric-awesome-show-great-job/beaver-boys-twins.html
and here's your answer: http://en.wikipedia.org/wiki/Birthday_problem
Thank you. I looked at the math involved in Wiki article and it is quite complicated. It says the probability is 99% of two people having the same birthday with just 57 people in the room. That seems odd but I can't question the math.
juice only matters when you lose