FreeFall
Double Post King
- Since
- Feb 4, 2010
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say I have an event:
85.71% or -600 to win
the odds I get are
-300 or 75%
according to kelly I should bet:
b=1.33 ; p=.8571 ; q=.1429 ;
((1.33)*(.8571)) - (.1429)
--------------------------------
(1.33)
= .7496 which would mean I bet 74.96% of my BR? I must be missing something. Also if you could explain why sometimes people use half kelly and if that is just dividing your resultant by two I would be grateful.
85.71% or -600 to win
the odds I get are
-300 or 75%
according to kelly I should bet:
b=1.33 ; p=.8571 ; q=.1429 ;
((1.33)*(.8571)) - (.1429)
--------------------------------
(1.33)
= .7496 which would mean I bet 74.96% of my BR? I must be missing something. Also if you could explain why sometimes people use half kelly and if that is just dividing your resultant by two I would be grateful.